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The oxidation state of N in H N O 3 is: A + 7 B + 1 0 C + 5 D + 3 The oxidation state of N in HNO3 is:A+7B+10C+5D+3
Dear student Let oxidation number of nitrogen=xOxidation number of hydrogen =+1Oxidation number of oxygen=−21+x+3×(−2)=0⇒x=+5C is correct option Good Luck
Let x be the oxidation number of N in nitric acid. The oxidation numbers of H and O in nitric acid are +1 and −2 respectively. The sum of the oxidation numbers is zero for the neutral molecule. Hence, 1+x+3(2−)=0 or, x=5
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