2 Answers
Vikas TU
Dear student
Let oxidation number of nitrogen=x
Oxidation number of hydrogen =+1
Oxidation number of oxygen=−2
1+x+3×(−2)=0
⇒x=+5
Let oxidation number of nitrogen=x
Oxidation number of hydrogen =+1
Oxidation number of oxygen=−2
1+x+3×(−2)=0
⇒x=+5
C is correct option
Good Luck
ankit singh
Let x be the oxidation number of N in nitric acid.
The oxidation numbers of H and O in nitric acid are +1 and −2 respectively. The sum of the oxidation numbers is zero for the neutral molecule.
Hence, 1+x+3(2−)=0
or, x=5
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