The ionization energy of a hydrogen atom is 13.6 eV. Find the energy of the third lowest electronic level in doubly ionized lithium (Z = 3)

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Arun · Answer

Dear student E = -13.6Z^2/n^2 and Z = 3, n = 3, so energy remains -13.6 eV Hope it helps Regards Arun (askIITians forum expert)

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The ionization energy of a hydrogen atom is 13.6 eV. Find the energy of the third lowest electronic level in doubly ionized lithium (Z = 3)

The ionization energy of a hydrogen atom is 13.6 eV. Find the energy of the third lowest electronic level in doubly ionized lithium (Z = 3)

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The ionization energy of a hydrogen atom is 13.6 eV. Find the energy of the third lowest electronic level in doubly ionized lithium (Z = 3)

The ionization energy of a hydrogen atom is 13.6 eV. Find the energy of the third lowest electronic level in doubly ionized lithium (Z = 3)

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