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the hybridization of phosphorus in PCl 5 (in solid state ) is 1)sp 3 2)sp 3 d 2 3)sp 3 d 4)both 1 and 2

the hybridization of phosphorus in PCl5 (in solid state ) is
1)sp3
2)sp3d2
3)sp3d
4)both 1 and 2

Grade:12

22 Answers

Umakant biswal
5359 Points
5 years ago
@ krishna 
option no 3 turns out to be the correct option , here , the orbitals are filled by electrons of five cl atom . 
there are 5 p-cl sigma bond , three in one plane and make an angle of 120 degree , these are called as equitorial . 
HOPE IT CLEARS 
ALL THE BEST ..
krishna priya
51 Points
5 years ago
ans is given as 4
Ankur Saha
56 Points
5 years ago
Ans. is opt.no. 3) sp3d There are 5 sigma bonds and no loan pair of electron...
krishna priya
51 Points
5 years ago
does it show ionic charecter in solid state?----
Gavvala Ganesh
551 Points
5 years ago
I hope to option no 3.because it has 5 sigma bonds and no lone pairs of electrons,here,the orbital are filled by electrons of five cl atoms
sahabudin ali
36 Points
5 years ago
i hope to no.3 because phosphours atom contain in last subshell is 5 electron and not contain a lone pair and here is 5 chlorine atom .then we add up eletron and we get a 10 and we devided by half and we get a 5.thesee means sp3d hyberdisation.
Alan thomas ve
22 Points
5 years ago
Each sp3d hybrid orbital will overlap with the p orbital of chlorine to form pcl5.
p=1s2 2s2 2p6 3s2 3p3 3d0.
aborah martin
22 Points
5 years ago
Sp3d. This is because hybridization depends on the lone pair of electrons on the central atom and the number of bonds it forms. P forms 5 bonds with no lone pair hence an sp3d hybridized. NB: each bond is counted as one VSEPR riule.
Sumaiya
19 Points
4 years ago
Since pcl5 has trigonal bipyramidal structure so appropriate hybridisation for this structure is sp3 . And second way to find hybridisation is "half (total valence e-+number of monovalent atom ) "
dolly bhatia
200 Points
4 years ago
sp3d is the right answer.
In excited state, intermixing of a 3s, three 3p and one 3d orbitals gives five half filled  sp3d hybrid orbitals, which are arranged in trigonal bipyramidal symmetry.
i.e. three orbitals are arranged in trigonal planar symmetry whereas remaining two are arranged perpendicularly above and below this plane.
 
MADHAV SAHI
38 Points
4 years ago
Answer is D ..PCl5 exist in 2 forms P(Cl)4 and P(Cl)6..So D is the right answer sp3 for P(Cl)4 and sp3d2 for P(Cl)6
anand Ravidas
11 Points
4 years ago
option 1 nd 2 is correct. This is because when we take PCl5 in solid state.... then we must consider n molecule of PCl5.... that is 2PCl5...further...... 2PCl5 break in PCl4+ and PCl6-and the hybridization of these are SP3 and SP3d2
Suraj Singh
148 Points
4 years ago
The correct answer is both 1 and 2 as in solid state PCl5 exists in the form of PCl4+ and PCl6-to increase its molecular bond by interionic attraction.. So it`s hybridisation is both sp3 and sp3d2
Kaustavbanerjee
11 Points
4 years ago
It should be option 4 as PCl5 exists in [PCl4]+ and [PCl6]- in solid state....as in first case it is Sp3 and that in second it is Sp3d2
Vijay Mishra
13 Points
4 years ago
Answer is OPTION 4 because in solid state pcl5 ionised into cation & anion Pcl4 pcl6 and hence it have both the configuration sp3 & sp3d2
Sayan Bhowmik
40 Points
4 years ago
The hybridisation no. Is 5 so it is sp3d..... Follow books if you didnt know how to find hybridisation state.
Sakshi
23 Points
4 years ago
Hybrid orbital =no.of sigma bond +no of lone pair, but in case of pcl5 there is no lone pair on the central bond so , only five sigma bond so, option 3 is correct
Sonal Priyanka
26 Points
4 years ago
(4) is the correct option because in solid state PCl5 exists as [PCl4][PCl6].Therefore for cation hybridisation is sp3 and for anion it is sp3d2.
Attaurehman Sahik
11 Points
4 years ago
Option 3 because here the steric no is 5. So phosphorus to obtain SP3d hybridisation and it depends on the number of terminal atoms .By Sahil Attaurehman 
jagpreet singh
13 Points
3 years ago
option 4 is correct because in solid state the pcl5 exist as dimer pcl4+ pcl6- and in pcl4 + hybridisation is sp3 and in pcl6- hybridisation is sp3d
Shristi
15 Points
2 years ago
Ans.will be D...as in solid state pcl5 changes it's hybridization...it breaks in pcl4+(hybridization sp3) and pcl6- (hybridization sp3d2s p3 forms ionic bond between them
Tushar Mittal
13 Points
5 months ago
See in solid state it exist as (PCl6)(PCl4) hence we have sp3d2 and sp3  so the answer is clear last option will be the answer for the presence of two ions to give it a solid.

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