State with balanced equations, what happens when (i) Silver is treated with hot concentrated sulphuric acid. (ii) Ammonium dichromate is heated. (iii) Hydrogen sulphide is passed through a solution of potassium paramagnetic acidified with dilute sulphuric acid.

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Aditi Chauhan · Answer

(i) 2Ag + 2H 2 SO 4 &rarr; Ag 2 SO 4 + SO 2 + H 2 O (white) (ii) (NH 4 ) 2 Cr 2 O 7 Cr 2 O 3 + N 2 + 4H 2 O (green) (iii) 2KMnO 4 . + 3H &shy;2 SO 4 + 5H 2 S K 2 SO 4 + 2MnSO 4 + 5S + 8H 2 O (turbidity)

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State with balanced equations, what happens when (i) Silver is treated with hot concentrated sulphuric acid. (ii) Ammonium dichromate is heated. (iii) Hydrogen sulphide is passed through a solution of potassium paramagnetic acidified with dilute sulphuric acid.

State with balanced equations, what happens when
(i) Silver is treated with hot concentrated sulphuric acid.
(ii) Ammonium dichromate is heated.
(iii) Hydrogen sulphide is passed through a solution of potassium paramagnetic acidified with dilute sulphuric acid.

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State with balanced equations, what happens when (i) Silver is treated with hot concentrated sulphuric acid. (ii) Ammonium dichromate is heated. (iii) Hydrogen sulphide is passed through a solution of potassium paramagnetic acidified with dilute sulphuric acid.

State with balanced equations, what happens when(i) Silver is treated with hot concentrated sulphuric acid.(ii) Ammonium dichromate is heated.(iii) Hydrogen sulphide is passed through a solution of potassium paramagnetic acidified with dilute sulphuric acid.

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State with balanced equations, what happens when
(i) Silver is treated with hot concentrated sulphuric acid.
(ii) Ammonium dichromate is heated.
(iii) Hydrogen sulphide is passed through a solution of potassium paramagnetic acidified with dilute sulphuric acid.