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Firstly, sodium dichromate is reduced with sulphur dioxide. Secondly, alcohols are oxidised to the corresponding ketones. 3R2CHOH+ Cr2O7(2-) + 2H+ gives 3R2C=O+ Cr2O3 + 4H2OWhen heated strongly, sodium dichromate decomposes to form sodium chromate4Na2Cr2O7 gives 4Na2Cro4 + 2Cr2O3 + 3O2
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