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Hybridization of Cu(NH3)6 2+a/c to vbt Explain with details related to the chapter no. 9 rbse chemistry 1book
First ind the oxidation numebr for Cu that is here => +2 as NH3 has zero charge considered.Now the coordination number for the central atom Cu is 6.Which eventually defines that it has an Octahedral geometry.
C.N no.is 6 so it should be octahedral but due toh to John teller distortion it's geometry will be te tetragonally distorted octahedral
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