Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
(i)(A) is FeSO base 4.7H base 2O because it is light green crystalline solid. Which dissolves in water containing H base 2SO base 4
(ii) On strong heating FeSO base 4 both SO base 4 (B) and SO base 3 (C) are evolved. The colour of KMnO base 4 disappears due to the formation of MnSO base 4.
(iii) SO base 2 being a reducing agent turns a dichromate solution green and forms H base 2SO base 4 in the solution. SO base 3 dissolves in water to give H base 2SO base 4. Therefore, white ppt of BaSO base 4 is formed with a solution of Ba(NO base 3) base 2
(iv) The brown residue left behind (D) is Fe base 2O base 3 which is reduced to Fe on heating in charcoal cavity. Fe is magnetic substance.
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !