calculate the ph 0f final solution of following20 ml of 0.1M ch3cooh,Ka 1.8*10^-5
calculate the ph 0f final solution of following
20 ml of 0.1M ch3cooh,Ka 1.8*10^-5
nagaraj , 9 Years ago
Grade 12th pass
Inorganic Chemistry> calculate the ph 0f final solution of fol...
1 AnswersVikas TU
the a Ph becomes:
CH3COOH (aq) + H2O (l) 
CH3COO-(aq)+ H3O+(aq)
CH3COO-(aq)+ H3O+(aq) Ions 0.1M
-G +G +G
0.1 M -G +G +G
dissociation constant : Ka= 1.8*10^-5
[CH3COOH]
[H3O+][CH3COO]=1.8x10^5[CH3COOH]
[H3O+][CH3COO]=1.8x10^5[CH3COOH]Replacing with G
We have [G][G]/0.1-G =1.8x10^-5
Solving using the quadratic formula : G = 3.399 x 10^-5
pH = -log(G) = 4.4686
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