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An aqueous solution containing one mole of HgI base 2 and two moles of Nal is orange in colour. On addition of excess Nal the solution becomes colouress. The orange colour reappears on subsequent addition of NaOCI. Explain with equations.

An aqueous solution containing one mole of HgI base 2 and two moles of Nal is orange in colour. On addition of excess Nal the solution becomes colouress. The orange colour reappears on subsequent addition of NaOCI. Explain with equations.

Grade:12th pass

1 Answers

Kevin Nash
askIITians Faculty 332 Points
6 years ago

Sodium iodide on reaction with HgI base 2 gives colourless complex salt, Na base 2[HgI base 4]

HgI base 2 + 2NaI ? Na base 2[HgI base 4]

Colour is due to presence of residual HgI base 2

But on addition of excess NaI, it becomes colourless due to change of residual HgI base 2 into Na base 2[HgI base 4]

HgI base 2 + 2Nal (excess) ? Na base 2[HgI base 4] (colourless)

The orange colour of HgI base 2 reappears due to conversion of Na base 2[HgI base 4] into HgI base 2 by means of NaOCI

3Na base 2HgI base 4 + 2NaOCI + 2H base 2O ? 3HgI base 2 +2NaCI + 4NaOH +2NaI base 3

Orange colour

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