Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
Sodium iodide on reaction with HgI base 2 gives colourless complex salt, Na base 2[HgI base 4]
HgI base 2 + 2NaI ? Na base 2[HgI base 4]
Colour is due to presence of residual HgI base 2
But on addition of excess NaI, it becomes colourless due to change of residual HgI base 2 into Na base 2[HgI base 4]
HgI base 2 + 2Nal (excess) ? Na base 2[HgI base 4] (colourless)
The orange colour of HgI base 2 reappears due to conversion of Na base 2[HgI base 4] into HgI base 2 by means of NaOCI
3Na base 2HgI base 4 + 2NaOCI + 2H base 2O ? 3HgI base 2 +2NaCI + 4NaOH +2NaI base 3
Orange colour
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !