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a welding fuel gas contains carbon and hydrogen only. burning a small sample of it in oxygen gives 3.38 g carbon dioxide, 0.69 g of water and no other products. A volume of 10L(measured at STP) of this welding gas is found to weigh 11.6 g. calculate its empirical formula
moles at STP = 10/22.4 => 0.44642Apply POAC on carbon after, 0.44642 * x = 1 * 3.38/44x = 0.076818/0.44642 = 0.172076for hydrogn u will get too 0.172076Hence EPIROCAL formulae becomes=>0.1720(CH)=> CH.
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