60 ml of mixture of CO and H2 were mixed with 40 ml of oxygen. Mixture was exploded and after cooling volume was found to be 30 ml. Find the volume of CO and H2. (If all the volume are measured at STP).

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varun · Answer

Hello kumar brahma Let the volume of mixture of CO be a ml the volume of mixture be b ml therefore a+b=60ml Now CO + ½ H2 gives CO2 and then H2 + ½ O2 gives H2O Afer cooling,the volume is found to be 30ml therefore a+{40-(a/2 + b/2)} = 30 afer solving you get 10=b/2 – a/2 b-a=20 ml therefore b=40 ml and a=20 ml Therefore volume of CO=20 ml and volume of H2=40ml THANK YOU

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60 ml of mixture of CO and H2 were mixed with 40 ml of oxygen. Mixture was exploded and after cooling volume was found to be 30 ml. Find the volume of CO and H2. (If all the volume are measured at STP).

60 ml of mixture of CO and H2 were mixed with 40 ml of oxygen. Mixture was exploded and after cooling volume was found to be 30 ml. Find the volume of CO and H2. (If all the volume are measured at STP).

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60 ml of mixture of CO and H2 were mixed with 40 ml of oxygen. Mixture was exploded and after cooling volume was found to be 30 ml. Find the volume of CO and H2. (If all the volume are measured at STP).

60 ml of mixture of CO and H2 were mixed with 40 ml of oxygen. Mixture was exploded and after cooling volume was found to be 30 ml. Find the volume of CO and H2. (If all the volume are measured at STP).

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