Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

50 ml of pure and dry oxygen gas was subjected to electric discharge and on cooling to original temperature the volume of ozonized oxygen was found to be 47 ml. The gas was then brought in contact with turpentine oil the remaining gas occupied a volume of 41 ml. Find molecular formula of ozone

50 ml of pure and dry oxygen gas was subjected to electric discharge and on cooling to original temperature the volume of ozonized oxygen was found to be 47 ml. The gas was then brought in contact with turpentine oil the remaining gas occupied a volume of 41 ml. Find molecular formula of ozone

Grade:11

1 Answers

Arun
25763 Points
one year ago
The reaction of oxygen to ozone can be shown as:
 
3O_2 -> 2O_3
 
Now, for 90 ml of O_2 volume of Ozone = 90*2/3 = 60 ml
 
Only 10% O_3 is converted and can be shown as:
 
Volume of ozone = 10 % of 60 = 6 ml.
 
Hence,
 
AFter some time the remaining volume of ozone = 6 mL
 
Volume of oxygen = 90 – 6 = 84 mL

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free