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271
When a solution of propionic acid is half neutralized with NaOH, the pH equals
4.87. what is the dissociation constant of acid?

ajay , 8 Years ago
Grade 12th pass
anser 1 Answers
Vikas TU

Last Activity: 8 Years ago

Half of propanoic acid gets neutralized.
Hence for a mol of propanoic acid a/2 mol left.
 
4.87 = -log[H+]
-log((ka * CH3 – CH2 – COOH)/(CH3COO-)) = 4.87
On solving we get,
Ka = 10^-4.87/2.

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