Sir,I am so thankful to you for patiently clearing my doubts.

now can you explain (send) me Molecular orbital energy diagram of oxygen and nitrogen?

Dear jaisson

Nitrogen:

This molecule has ten electrons. The atomic orbitals combine to produce the following molecular orbital diagram

Here the 2p_g orbital is occupied by two electrons to give a total bond order of three. This corresponds well with the Lewis structure (), although the orbital approach tells us that there is one s and two p.

Oxygen:

This molecule has twelve electrons, two more than nitrogen - and these extra two are placed in a pair of degenerate p_g orbitals. The atomic orbitals combine to produce the following molecular orbital diagram:

Comparison of the above energy level diagram wit hthat for nitrogen - you can see that the 2s_g level lies lower than p_u. Here, we are starting to fill the anti-bonding orbitals originating from the p orbital interactions and so the bond order decreases from three to two.
The lowest energy arrangment (Hund's rule) - has a single electron, each with parallel spins, in each of the p_g^x and p_g^y orbitals. This produces a paramagnetic molecule, with a double bond and has two unpaired electrons.

Please feel free to post as many doubts on our discussion forum as you can.

If you find any question Difficult to understand -

post it here and we will get you the answer and detailed solution very quickly.
 We are all IITians and here to help you in your IIT JEE preparation.

 All the best.
 
Regards,
Askiitians Experts
Badiuddin