Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
dear priyanka dubey
according to the given information the equationbecomes as
2A+B=3C+D
FROM THIS Kc EQUALS TO [D][C]^3 DIVIDED BY [B][A]^2
APPROVE IF CORRECT PLEASE
CONSIDER THE INTIAL MOLES OF ''A'' BE ''a'' AND MOLES OF ''B'' BE ''b'' AND MOLES LOST BY ''A'' AND ''B'' BE X
A + B ----------------> C + D
INITIAL MOLES: a b 0 0
EQUILIBRIUM MOLES : a-x b-x 0+x 0+x
ACCORDING TO STICHIOMETERY AND SINCE THE COEFFICIENTS ARE 1 IF X MOLES ARE LOST BY ''B'' SO ''A'' WILL ALSO LOSE X MOLES
IT DOESNOT MATTER IF YOU WORK IN MOLES OR CONCENTRATION BECAUSE IT IS SAMETHING
ACCORDING TO THE INFORMATION a=2b AND (0+x)=3(b-x) SO FROM THIS EQUATION YOU GET THE VALUE OF x WHICH IS (3b)/4
NOW KC= [C]1 [D]1 DIVIDE BY [A]1 [B]1 [ ] SIGN INDICATES MOLAR CONCENTRATION
KC= x * x divide by (a-x) (b-x)
i didnt write the concentration which is moles upon volume beacuse volume term gets cancelled so now you have ''a'' in terms ''b'' and ''x'' in terms of ''b'' substitue those values in the equation and ''b'' term wil get cancelled and you will get your answer
PLZ DO APPROVE THE ANSWER IF YOU ARE SATISFIED
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !