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Alkaline earth metals always form dipositive ions due to (a) IE 2 - IE 1 > 10 eV (b) IE 2 - IE 1 = 17 eV (c) IE 2 - IE 1 pls give answer & explain the reason of your answer.

Alkaline earth metals always form dipositive ions due to


(a) IE2 - IE1 > 10 eV   (b) IE2 - IE1 = 17 eV     (c)  IE2 - IE1 < 10 eV     (d) None of these


pls give answer & explain the reason of your answer. 

Grade:11

1 Answers

Sunil Kumar FP
askIITians Faculty 183 Points
9 years ago
Although IE1 (first ionization energy) values of alkaline earth metals are higher than that of alkali metals, the IE2 (second ionization energy) values of alkaline earth metals are much smaller than those of alkali metals. This occurs because in alkali metals the second electron is to be removed from a cation, which has already acquired a noble gas configuration. In the case of alkaline earth metals the second electron is to be removed from a monovalent cation, which still has one electron in the outermost shell. Thus, the second electron can be removed more easily in the case of group 2 elements than in group 1 elements
the answer of this question is C
ex-IE1 value of Mg=7.6ev
IE2 value for Mg=15ev
difference is 8ev that is less than 10ev

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