Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
What is oxidation number?and how do we get this? What is oxidation number?and how do we get this?
What is oxidation number?and how do we get this?
Dear student, Electrochemical reactions involve the transfer of electrons. Mass and charge are conserved when balancing these reactions, but you need to know which atoms are oxidized and which atoms are reduced during the reaction. Oxidation numbers are used to keep track of how many electrons are lost or gained by each atom.
Dear student,
Electrochemical reactions involve the transfer of electrons. Mass and charge are conserved when balancing these reactions, but you need to know which atoms are oxidized and which atoms are reduced during the reaction. Oxidation numbers are used to keep track of how many electrons are lost or gained by each atom.
Oxidising number is the number of electrons gained or lost by an element or compound. For example - oxidation number of oxygen is -2 it means it can gain two electrons to complete its octate to get stability. or Number of electrons required by an element to complete its octate. Example - In H2SO4 we have to find oxidising number of sulphur. Let us suppose it is 'x' then (+1*2) + (x) + (4* -2)= 0 [where 4 and 2 are the number of atoms, while +1 and -2 are oxidation numbers of hydrogen and oxygen] By solving it, we get x = +6 This is oxidation number of sulphur.
Oxidising number is the number of electrons gained or lost by an element or compound. For example - oxidation number of oxygen is -2 it means it can gain two electrons to complete its octate to get stability. or Number of electrons required by an element to complete its octate.
Example - In H2SO4 we have to find oxidising number of sulphur.
Let us suppose it is 'x' then (+1*2) + (x) + (4* -2)= 0
[where 4 and 2 are the number of atoms, while +1 and -2 are oxidation numbers of hydrogen and oxygen]
By solving it, we get x = +6
This is oxidation number of sulphur.
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -