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How is photoelectron energy related to excitation wavelength?
A photoelectron is an electron that is ejected from a substance (most often an alkali metal) after it absorbs electromagnetic radiation. In this case, shining violet light on cesium causes ejection of electrons. Some of the energy of the light goes into jarring the electron free of the metal; the rest appears as kinetic energy of the electron:
Dear Ravi,
Photoelectron energy refers to the kinetic energy of the electron emitted from the metal surface on being excited by the photons of required wavelength.
According to Einstein,
hc / = ø + KE
where h = planks constant
c = speed of light
= wavelength of the incident photon .
ø = work function of the material.
KE = kinetic energy of photoelectronsA
Therefore on increasing the excitation wavelength energy of the incident photon decreases and hence the photoelectron energy decreases i.e. photoelectron energy is inversely related to excitation wavelength.
Thank you.
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