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1g of the acid C6 H10 O4 requires 0.768g of KOH for complete neutralization. How many neutralizable Hydrogen Atoms are present in the molecule?

1g of the acid C6 H10 O4 requires 0.768g of KOH for complete neutralization. How many neutralizable Hydrogen Atoms are present in the molecule?

Grade:11

1 Answers

Vikas TU
14149 Points
4 years ago
Hiii 
No. of equivalents = n. of moles * valency factor
By equivalence concept 
No. of equivalents of C6H10O4 = No. of equivalents of KOH 
No. of moles * vlency factor = no. of moles of KOH
n* 1/146 = 1* 0.768/56
n=2
Hence no. of unstable hydrogen in C6H10O4 = 2

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