X coordinate of incentre of a triangle that has coordinates of midpoint of its sides as (0,1)(1,1) (1,0) is :

Question

Sunil Kumar FP · Answer

thanks and regards sunil kr askIItian faculty

Kushagra Madhukar · Answer

Dear student, Please find the solution to your problem. The coordinates of the triangle using the mid points of sides are A : (0, 0) B : (0, 2) C : (2, 0) Let the length of opposite sides be a, b, c. Length of side of triangle a = √[(0 – 2) 2 + (2 – 0) 2 ] = 2 √ 2 b = √[(0 – 2) 2 + (0 – 0) 2 ] = 2 c = √[(0 – 0) 2 + (0 – 2) 2 ] = 2 x co-ordinate of incenter = (ax a + bx b + cx c )/(a + b + c) = 2 √ 2.0 + 2.0 + 2.2/(4 + 2 √ 2) = 4/(4 + 2 √ 2) = 2/(2 + √ 2) = 2(2 – √ 2)/(4 – 2) = 2 – √ 2 Thanks and regards, Kushagra

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X coordinate of incentre of a triangle that has coordinates of midpoint of its sides as (0,1)(1,1) (1,0) is :

X coordinate of incentre of a triangle that has coordinates of midpoint of its sides as (0,1)(1,1) (1,0) is :

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