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X coordinate of incentre of a triangle that has coordinates of midpoint of its sides as (0,1)(1,1) (1,0) is :

ashwini , 11 Years ago
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anser 2 Answers
Sunil Kumar FP

204-1392_20140320_064833.jpg

thanks and regards
sunil kr
askIItian faculty
Last Activity: 11 Years ago
Kushagra Madhukar
Dear student,
Please find the solution to your problem.
 
The coordinates of the triangle using the mid points of sides are
A : (0, 0)
B : (0, 2)
C : (2, 0)
Let the length of opposite sides be a, b, c.
Length of side of triangle 
a = √[(0 – 2)2 + (2 – 0)2] = 22
b = √[(0 – 2)2 + (0 – 0)2] = 2
c = √[(0 – 0)2 + (0 – 2)2] = 2
x co-ordinate of incenter = (axa + bxb + cxc)/(a + b + c)
= 22.0 + 2.0 + 2.2/(4 + 22)
= 4/(4 + 22)
= 2/(2 + 2)
= 2(2 – 2)/(4 – 2)
= 2 – 2
 
Thanks and regards,
Kushagra
Last Activity: 5 Years ago
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