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X coordinate of incentre of a triangle that has coordinates of midpoint of its sides as (0,1)(1,1) (1,0) is :
thanks and regardssunil kraskIItian faculty
Dear student,Please find the solution to your problem. The coordinates of the triangle using the mid points of sides areA : (0, 0)B : (0, 2)C : (2, 0)Let the length of opposite sides be a, b, c.Length of side of triangle a = √[(0 – 2)2 + (2 – 0)2] = 2√2b = √[(0 – 2)2 + (0 – 0)2] = 2c = √[(0 – 0)2 + (0 – 2)2] = 2x co-ordinate of incenter = (axa + bxb + cxc)/(a + b + c)= 2√2.0 + 2.0 + 2.2/(4 + 2√2)= 4/(4 + 2√2)= 2/(2 + √2)= 2(2 – √2)/(4 – 2)= 2 – √2 Thanks and regards,Kushagra
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