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`        We have 21 identical balls which needs to be distributed among 3 boys A,B,C such that A always gets even number of balls.Number of possible ways of doing this is less than or equal to.`
10 months ago

Yash Patil
33 Points
```							162 ways. No of Balls With A = 2Balls Left = 19ways of sharing 19 identical balls with B and C= 18 this one case , so total cases = 9 , But its not stated that B or C can be or cant be with no balls .Assuming the can have no balls , total cases = 9 So total ways = 9x18= 162 less than or equal to 162
```
10 months ago
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