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Grade: 11
        
We have 21 identical balls which needs to be distributed among 3 boys A,B,C such that A always gets even number of balls.Number of possible ways of doing this is less than or equal to.
10 months ago

Answers : (1)

Yash Patil
33 Points
							
162 ways.
 
No of Balls With A = 2
Balls Left = 19
ways of sharing 19 identical balls with B and C= 18
 
this one case , so total cases = 9 , But its not stated that B or C can be or cant be with no balls .
Assuming the can have no balls , total cases = 9
 
So total ways = 9x18= 162
 
less than or equal to 162
10 months ago
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