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`        Two  pendulum have time period t and 5T/4 they starts SHM  at the same time from the mean position the phase difference between them after the pendulum with larger period  completes one oscillation is`
10 months ago

Arun
22557 Points
```							Since, bigger pendulum completes one oscillation, it's phase is 2 pi………….(1)The angular frequency of smaller pendulum isw=2 pi/T. Therefore , it's phase at time 5T/4 is (according to phase equals to wt)w 5T/4=( 2 pi/T)(5 T/4)=2.5 pi…………(2)From (1) and (2) the difference in phase is ( pai/2).
```
10 months ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions