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`        The temperature at which the speed of the sound in air becomes double of its value at 27 degree celsius is`
one year ago

## Answers : (1)

Arun
23513 Points
```							Use the formula velocity of sound waves v = sqrt (P/rho) P is the pressure and rho is the density.Write this as v1 = root(p1/rho) v2= root (p2/rho) square both sides v1^2 = p1 /rho v2^2 = p2/rho Take the ration v1^2/v2^2 = p1/p2 Put the values v1=1 and v2 = 2 YOu get 1/4 = p1/p2 p1 = n kb T1 and p2= n kb T2. Here n is the number density. kb Boltzmann constant and T1 and T2 are temperatures. If you use it in the above equation you get T2= 4 T1 T1 is 27 degrees= 273 + 27 = 300 T2= 1200 degrees = 1200-273 = 927 degrees.
```
one year ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions