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The temperature at which the speed of the sound in air becomes double of its value at 27 degree celsius is
9 months ago

Use the formula
velocity of sound waves v = sqrt (P/rho)

P is the pressure and rho is the density.Write this as

v1 = root(p1/rho)
v2= root (p2/rho)

square both sides

v1^2 = p1 /rho

v2^2 = p2/rho

Take the ration

v1^2/v2^2 = p1/p2

Put the values v1=1 and v2 = 2

YOu get

1/4 = p1/p2

p1 = n kb T1 and p2= n kb T2. Here n is the number density. kb Boltzmann constant and T1 and T2 are temperatures.

If you use it in the above equation you get

T2= 4 T1

T1 is 27 degrees= 273 + 27 = 300

T2= 1200 degrees = 1200-273 = 927 degrees.
9 months ago
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