The relation between time t and distance x is t=ax^2+ BC where a and B are constants. Find the acceleration in terms of velocity(v).

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Himanshu Rathour · Answer

Given t=ax²+bc Differentiating above equation wrt x 1=2ax(dx/dt) dx/dt=v 1/2ax=v.....i Differentiating above equation wrt x dv/dx=-1/ax².....ii Now A=dv/dt Multiplying and dividing by dx A=v(dv/dx) .....iii From i ii & iii A=-1/2ax 3

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The relation between time t and distance x is t=ax^2+ BC where a and B are constants. Find the acceleration in terms of velocity(v).

The relation between time t and distance x is t=ax^2+ BC where a and B are constants. Find the acceleration in terms of velocity(v).

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The relation between time t and distance x is t=ax^2+ BC where a and B are constants. Find the acceleration in terms of velocity(v).

The relation between time t and distance x is t=ax^2+ BC where a and B are constants. Find the acceleration in terms of velocity(v).

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