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Intersection point of y = 0 with first line is the point B(-p, 0)
Intersection point of y = 0 with second line is the point A(-q, 0)
Intersection point of the two lines is the point C(pq, (p + 1)(q + 1))
Altitude from C to AB is x = pq
Altitude from B to AC is y = -q/1+q (x + p)
On solving these two we get x = pq and y = -pq
=> locus of orthocenter is x + y = 0.
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