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The average molar mass of a mixture of methane and ethene present in the ratio a:b is found to be 20 g/mol. If the ration were reversed, what would be the molar mass of the mixture?

The average molar mass of a mixture of methane and ethene present in the ratio a:b is found to be 20 g/mol.  If the ration were reversed, what would be the molar mass of the mixture? 

Grade:11

2 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
7 years ago

Arun Kumar
IIT Delhi
Askiitians Faculty
Rishi Sharma
askIITians Faculty 646 Points
one year ago
Dear Student,
Please find below the solution to your problem.

Molar mass of methane = 16 gmol^-1
Molar mass of ethane = 28 gmol^-1
When they are present in the a:b their average molar mass
= (ax16 + bx28)/(a+b) = 20
i.e., 16a + 28b = 20(a+b)
or 4a + 7b = 5 (a+b)
or a = 2b
or a/b = 2/1 = 2:1
If the ratio is reversed, now the ratio
a:b = 1:2
Average molar mass = 1x16 + 2x28/1+2
= 24 gmol^-1

Thanks and Regards

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