Spring balance reads 10kg in a bucket of water is suspended from it what will be the reading of the balance when an iron piece of mass 7.2 kg suspended by a string is immersed within half its volume inside the water in the bucket relative density of the iron is 7.2

Question

Arun · Answer

Mass of iron piece = 7.2 kg
Density of iron = Mass × Volume

Volume of iron piece = 7.2/7.2×10 = 10^-3 kg^3

Volume of iron immersed = 10^-3/2 =

Mass of water displaced by iron piece = 10^-3/2 × 10^3 = 0.5 kg

Now, reading in spring balance = 10+0.5 = 10.5kg

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Spring balance reads 10kg in a bucket of water is suspended from it what will be the reading of the balance when an iron piece of mass 7.2 kg suspended by a string is immersed within half its volume inside the water in the bucket relative density of the iron is 7.2

Spring balance reads 10kg in a bucket of water is suspended from it what will be the reading of the balance when an iron piece of mass 7.2 kg suspended by a string is immersed within half its volume inside the water in the bucket relative density of the iron is 7.2

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Spring balance reads 10kg in a bucket of water is suspended from it what will be the reading of the balance when an iron piece of mass 7.2 kg suspended by a string is immersed within half its volume inside the water in the bucket relative density of the iron is 7.2

Spring balance reads 10kg in a bucket of water is suspended from it what will be the reading of the balance when an iron piece of mass 7.2 kg suspended by a string is immersed within half its volume inside the water in the bucket relative density of the iron is 7.2

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