Equation of the plane through the line (x-1)/3 = (y-4)/2 = (z-4)/-2 & parallel to the line (x+1)/2 = (1-y)/4 = (z+2)/1. Hence, find the shortest distance between the lines.

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Deepak Kumar Shringi · Answer

use the formula of find minimum distance between two skew lines use formula d=(a2-a1).(b1*b2)/mod(b1*b2) where a1,a2 are point from line is passing and b1 and b2 are parellel vectors

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Equation of the plane through the line (x-1)/3 = (y-4)/2 = (z-4)/-2 & parallel to the line (x+1)/2 = (1-y)/4 = (z+2)/1. Hence, find the shortest distance between the lines.

Equation of the plane through the line (x-1)/3 = (y-4)/2 = (z-4)/-2 & parallel to the line (x+1)/2 = (1-y)/4 = (z+2)/1. Hence, find the shortest distance between the lines.

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Equation of the plane through the line (x-1)/3 = (y-4)/2 = (z-4)/-2 & parallel to the line (x+1)/2 = (1-y)/4 = (z+2)/1. Hence, find the shortest distance between the lines.

Equation of the plane through the line (x-1)/3 = (y-4)/2 = (z-4)/-2 & parallel to the line (x+1)/2 = (1-y)/4 = (z+2)/1. Hence, find the shortest distance between the lines.

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