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A stone is thrown upward with initial velocity 25 m/sec along a tower another stone is thrown downward from the top of the tower when and where they meet

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3 years ago

Arun
25768 Points
```							let height of tower is H, acceleration due to gravity is a, case 1) initial velocity is −u (assuming downward direction as positive.then H=−ut+ 21​  at 2 =>H=−5u+ 225​  afor case 2) initial velocity is uthen H=ut+ 21​  at 2 =>H=u+ 21​  amultiplying 2nd with 5 and adding both equation we get 6H=15a=>H=2.5anow for 3rd case u=0, we get 2.5a= 21​  at 2 =>t= 5​  sec.
```
7 months ago
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• Previous Year Exam Questions