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Grade: 9

                        

A stone is thrown upward with initial velocity 25 m/sec along a tower another stone is thrown downward from the top of the tower when and where they meet

3 years ago

Answers : (1)

Arun
24742 Points
							
let height of tower is H, acceleration due to gravity is a, 
case 1) initial velocity is −u (assuming downward direction as positive.
then H=−ut+ 
2
1
​ 
 at 
2
 =>H=−5u+ 
2
25
​ 
 a
for case 2) initial velocity is u
then H=ut+ 
2
1
​ 
 at 
2
 =>H=u+ 
2
1
​ 
 a
multiplying 2nd with 5 and adding both equation we get 
6H=15a=>H=2.5a
now for 3rd case u=0, we get 2.5a= 
2
1
​ 
 at 
2
 =>t= 
5
​ 
 sec.
4 months ago
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