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A projectile is projected at an angle(a>45°) with an initial velocity u. The time t,at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is?
A projectile is projected at an angle(a>45°) with an initial velocity u. The time t,at which its magnitude of horizontal velocity will equal the magnitude of vertical velocity is?

```
4 years ago

Kiranchandar
11 Points
```							Assuming zero air resistance, we can take the horizontal component of its velocity as constant until it hits the ground. So we have the horizontal component as uCosA (Let the angle be A).And the vertical component at any given time t will be uSinA-gt.Equating the two, we get uSinA-gt = uCosAt = u(SinA-CosA)/g
```
4 years ago
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