A particle of mass 10² Kg is moving along the positive x-axis under the influence of a force F(x) = -k/2x² where k= 10-² NM² . at time t=0 it is at x=1.0 m and its velocity is v=0 (a) Find its velocity when it reaches x= 0.5 m

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Shivam · Answer

Change in Kinetic energy = work done ½ mv 2 – 1/2 mu 2 =∫ F.dx =>1/2 m(v f 2 -v 2 ) = [k/x 3] ] ½ * 10 2 (v f 2 )= 10 -2 /(1/.125 – 1/1) v f 2= 14 * 10 -4 v f = 3.74 * 10 -2 m/s

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A particle of mass 10² Kg is moving along the positive x-axis under the influence of a force F(x) = -k/2x² where k= 10-² NM² . at time t=0 it is at x=1.0 m and its velocity is v=0 (a) Find its velocity when it reaches x= 0.5 m

A particle of mass 10² Kg is moving along the positive x-axis under the influence of a force F(x) = -k/2x² where k= 10-² NM² . at time t=0 it is at x=1.0 m and its velocity is v=0 (a) Find its velocity when it reaches x= 0.5 m

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A particle of mass 10² Kg is moving along the positive x-axis under the influence of a force F(x) = -k/2x² where k= 10-² NM² . at time t=0 it is at x=1.0 m and its velocity is v=0 (a) Find its velocity when it reaches x= 0.5 m

A particle of mass 10² Kg is moving along the positive x-axis under the influence of a force F(x) = -k/2x² where k= 10-² NM² . at time t=0 it is at x=1.0 m and its velocity is v=0 (a) Find its velocity when it reaches x= 0.5 m

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