A long solenoid is fabricated. By closely winding a wire of diameter 0.5mm over a cylindrical frame so that successive turns nearly touch each other what would be magnetic field at center of solenoid if it carries a current of 2.5A

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Yuvraj Sharma · Answer

n=1/10^-3=10^3 B=4π*10^-7*10^3*5 =2π*10^-3T So,it is our answer 2π*10^-3T Thank you T is unit telsa 1T=10^4gauss

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A long solenoid is fabricated. By closely winding a wire of diameter 0.5mm over a cylindrical frame so that successive turns nearly touch each other what would be magnetic field at center of solenoid if it carries a current of 2.5A

A long solenoid is fabricated. By closely winding a wire of diameter 0.5mm over a cylindrical frame so that successive turns nearly touch each other what would be magnetic field at center of solenoid if it carries a current of 2.5A

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A long solenoid is fabricated. By closely winding a wire of diameter 0.5mm over a cylindrical frame so that successive turns nearly touch each other what would be magnetic field at center of solenoid if it carries a current of 2.5A

A long solenoid is fabricated. By closely winding a wire of diameter 0.5mm over a cylindrical frame so that successive turns nearly touch each other what would be magnetic field at center of solenoid if it carries a current of 2.5A

1 Answers

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