A cube of wood supporting 200gm mass just floats in water when the mass is removed cube rises by 2 cm if the size of the cube is x cm find x/5

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This means that the volume of water of depth 2cm and cross sectional area x^2 was supplying the necessary buoyant force needed to balance the 200gm mass.If g be acceleration due to gravity then: (volume of water)X(density of water)Xg=200Xg 2Xx^2X1Xg=200Xg x^2=100 x=10 cm x/5=2 cm

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A cube of wood supporting 200gm mass just floats in water when the mass is removed cube rises by 2 cm if the size of the cube is x cm find x/5

A cube of wood supporting 200gm mass just floats in water when the mass is removed cube rises by 2 cm if the size of the cube is x cm find x/5

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A cube of wood supporting 200gm mass just floats in water when the mass is removed cube rises by 2 cm if the size of the cube is x cm find x/5

A cube of wood supporting 200gm mass just floats in water when the mass is removed cube rises by 2 cm if the size of the cube is x cm find x/5

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