Click to Chat

1800-1023-196

+91-120-4616500

CART 0

• 0

MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping
`        A boy of mass 60 kg is standing over a platform of a mass 40 kg placed over a smooth horizontal surface he  throws a stone of mass 1 kg velocity v is equal to 10 m s to the power minus 1 at an angle of 45 degree with respect to the ground the displacement of a platform with boy on the horizontal surface when the stone lands on the groand isPlease explain the meaning of question`
10 months ago

Arun
22533 Points
```							 total mass of body and plateform = 100kg conservation of momentum in horizontal direction     100V + 1*10cos45 =0                                                                               V=-1/10√2 m/sec  negative sign indicates in the reverse direction. time  of filght = 2*10 sin 45 /10                    = √2 so in this time plateform will move  = V*t                                                    = 1/10√2 * √2                                                    = .1 m = 10 cm Answer
```
10 months ago
Think You Can Provide A Better Answer ?

## Other Related Questions on IIT JEE Entrance Exam

View all Questions »

### Course Features

• 731 Video Lectures
• Revision Notes
• Previous Year Papers
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Test paper with Video Solution

### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions