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```
A bob of mass M is suspended by a masslessstring of length L . The horizontal velocityat position 4 is just sufficient to make itreach the point The angle θ at which thespeed of the bob is half of that at A, satisfiesa)theta=pi/4 b)pi/4

```
3 years ago

Arun
25768 Points
```							If you see in the diagram,You get(1/2)* 5 mgl = (1/2)* m* (5gl/4) + mgl (1- cosθ)On solvingCos θ = - 7/8Henceθ > 3π4θπHope it helps
```
3 years ago
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### Course Features

• 731 Video Lectures
• Revision Notes
• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions