A galvanometer of resistance 20 W gives full scale detlection with a current of 0.004 A. To convert it into an ammeter of range 1 A, the required shunt resistance should be

        (d)    0.38 ohm

        (b)    0.21 ohm

        (c)    0.08 ohm

(d)    0.05 ohm

Question

A galvanometer of resistance 20 W gives full scale detlection with a current of 0.004 A. To convert it into an ammeter of range 1 A, the required shunt resistance should be

(d) 0.38 ohm

(b) 0.21 ohm

(c) 0.08 ohm

(d) 0.05 ohm

Kevin Nash · Answer

(c)

Maximum current which can pass through galvanometer,

Ig = 0.004 A

Let R be the resistance of shunt.

We know potential drop across AB = Potential drop across CD

R (I -Ig) = Ig (20)

Þ R(1- 0.004) = 0.004 × 20 Þ R = 0.08 W

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A galvanometer of resistance 20 W gives full scale detlection with a current of 0.004 A. To convert it into an ammeter of range 1 A, the required shunt resistance should be (d) 0.38 ohm (b) 0.21 ohm (c) 0.08 ohm (d) 0.05 ohm

A galvanometer of resistance 20 W gives full scale detlection with a current of 0.004 A. To convert it into an ammeter of range 1 A, the required shunt resistance should be

        (d)    0.38 ohm

        (b)    0.21 ohm

        (c)    0.08 ohm

(d)    0.05 ohm

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