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Grade 11IIT JEE Entrance Exam

A particle of mass M is moving in a horizontal circle of radius R with uniform speed V. When it moves from one point to a diametrically opposite point, its

(a) Kinetic energy change by MV2/4

(b) Momentum does not change

(c) Momentum changes by 2 MV

(d) Kinetic energy changes by MV2

Profile image of Simran Bhatia
12 Years agoGrade 11
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1 Answer

Profile image of Hrishant Goswami
12 Years ago

(c)

On the diametrically opposite points, the velocities have same magnitude but opposite directions. Therefore, change in momentum is MV-(- MV) = 2MV

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