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Grade 10IIT JEE Entrance Exam

A conductor of length 0.4 m is moving with a speed of 7 m/s perpendicular to a magnetic field of intensity 0.9 Wb/m2. The induced e.m.f. across the conductor is

(a) 1.26 V

(b) 2.52 V

(c) 5.04 V

(d) 252 V

Profile image of Aditi Chauhan
12 Years agoGrade 10
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1 Answer

Profile image of Simran Bhatia
12 Years ago

(b)

Length of conductor () = 0.4 m;

Speed (v) = 7 m/s and magnetic field (B) = 0.9 Wb/m2.

Induced e.m.f. (V) = B/v sin B = 0.9 × 004 × 7 × sin 90° = 2.52 V.

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