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find the equation to the circle which has its centre at the point (3,4) and touches the straight line,5x+12y-4=0.

prince parihar , 12 Years ago
Grade 11
anser 1 Answers
ruchi yadav

Last Activity: 11 Years ago

If straight line touches straight 5x+12y-4=0 so distance of line from center (3,4) will be radius of circle.

so radius will be = (15+48-4)/13 =4.5

so equation will be (x-3)2 + (y-4)2 = (4.5)2


Thank you,
Ruchi
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