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four different point on circle whose coordinate is (mi,1/mi) then which one is ture a. m 1 *m 2 *m 3 *m 4 =1 b.1/m 1 *1/m 2 *1/m 3 *1/m 4 =4

four different point on circle whose coordinate is (mi,1/mi) then which one is ture


a. m1*m2*m3*m4=1                b.1/m1*1/m2*1/m3*1/m4 =4

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2 Answers

Badiuddin askIITians.ismu Expert
148 Points
12 years ago

Dear nishant

for simplicity let equation of circle is x2 +y2 =r2

put (m,1/m) point

so  (m)2 +(1/m)2 =r2

simplify it

  m4 -r2m2 +1=0

this equation has 4 roots m1,m2,m3,m4

product of all roots

 m1*m2*m3*m4=1


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Badiuddin

AskiitianExpert Pramod-IIT-R
47 Points
12 years ago
Dear student Mr. Nishant for simplicity let equation of circle is x2 +y2 =r2 put (m,1/m) point so (m)2 +(1/m)2 =r2 simplify it m4 -r2m2 +1=0 this equation has 4 roots m1,m2,m3,m4 product of all roots m1*m2*m3*m4=1 Please feel free to post as many doubts on our discussion forum as you can. If you find any question Difficult to understand - post it here and we will get you the answer and detailed solution very quickly. We are all IITians and here to help you in your IIT JEE & AIEEE preparation. All the best. Regards, Askiitians Experts Pramod Kumar, IITR Alumni

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