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Grade Select GradeIIT JEE Entrance Exam

1.12 m of gas is produced at STP by the action of 4.12mg of alcohol with grignard's reagent. molecular mass of alcohol is?

Profile image of Yusuf Jamil
11 Years agoGrade Select Grade
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1 Answer

Profile image of Arun
6 Years ago
ROH + CH3MgI⟶ --------> CH4 + MgROI
 
22400mL of CH4 produced at STP
 
= 1mol of ROH
 
1.12mL of CH4 produced at STP = 1.12
 
/ 22400= 5×10−5 mol
 
Now molecular mass of ROH = 4.12×10^-3 /5*10^−5
 
∴ mol mass of ROH=82.4.
 
 

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