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0.145 gram of hydrocarbon is heated with dry copper oxide and 224 cm cube of CO2 was collected at STP the empirical formula for hydrocarbon

0.145 gram of hydrocarbon is heated with dry copper oxide and 224 cm cube of CO2 was collected at STP the empirical formula for hydrocarbon 

Grade:11

1 Answers

Arun
25750 Points
5 years ago
Sample X contains carbon and hydrogen only. (ii) Copper (II) oxide acts as oxidising agent.
(iii) 1. 22400 cm3 of CO2 at STP = 1 mole
∴ 224cm3 ofCO2 atSTP= 224 =0.01mole. 22400
2. 22400 cm3 of carbon dioxide contains carbon = 12 g
∴ 224 cm3 of carbon dioxide contains carbon = 12 × 224 22400
  = 0.12g 3. MassofhydrogeninsampleX=Massofhydrocarbon–
∴ Wt. of carbon in sample X = 0.12 g. Mass of carbon = (0.145 – 0.12) g = 0.025 g.
 
Element.      %age wt.         At. wt.         Relative no. of moles.         Simple ratio of atoms
C.                0.120 g.             12.               0.120 ÷ 12 = 0.01.              0.01 ÷ 0.01 = 1 or 2
H.                0.025 g.               1.               0.025 ÷ 1 = 0.025.            0.025 ÷ 0.01 = 2.5 or 5
 
hence empirical formula = C2H5

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