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what is fraction of initial kinetic energy remaining.

ujjwal raj , 11 Years ago
Grade 6
anser 2 Answers
Saurabh Koranglekar

Last Activity: 5 Years ago

Dear student

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Regards
Vikas TU

Last Activity: 5 Years ago

m1u1 = (m1 + m2)v.
Ef = ½ (m1 + m2)v2,
Ei = ½ m1u12.
Fraction of energy lost = (Ei - Ef)/Ei
= 1 - m1/(m1 + m2) = m2/(m1 + m2).
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