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`        the relation between time t and distance x for a particle moving in a straight line is t=ax2+ bx where a and b are constants . The retardation is?`
2 years ago

anemous
117 Points
```										redardation is 2a/(2ax+b)^3
```
2 years ago
noogler
489 Points
```										retardation is othing but negative acceleration.we know that v=dx/dt,al=dv/dt             v=velocity,al=acceleration,x=displacementfirst differentiate given eq.w.r.t. t1=2axdx/dt+dx/dt1=2axv+bv …..................(1)               v=1/2ax+bdifferentiate(1)  w.r.t. t0=2av2+2axal+bal .....................(2)substitute v=1/2ax+b in (2)2a/(2ax+b)2+(2ax+b)al=0(2ax+b)al= -2a/(2ax+b)2          al=-2a/(2ax+b)3                                        -ve sign indicates decrease in acceleration
```
2 years ago
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