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the position x of a particle along straight line is given as x = 3t^2-18t. the max speed in time interval t=0 to t=2 sec is?
3 years ago

Answers : (1)

Nicho priyatham
625 Points
							
given x=3t2-18t
so since v=dx/dt
we get v=6t-18
so in intrewal 0
so vmax=6(2)-18=-6 (neglect -sign coz it indicates direction)
so v max is 6
PLZZ APPROVE if useful and in case of any doubts put it in ans box
3 years ago
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