Grade 12th passGeneral Physics
The maximum and minimum magnitude of 2i+3j and 5i-2j
1 Answer
Shailendra Kumar Sharma
Two vectors A and B can give the resultant as
R2=A2+B2+2ABcos(theta)
R2=A2+B2+2ABcos(theta)
So the maximum is R=A+B and minimum is A-B
Now 2i+3j and 5i-2j has magnitude of 
=
and 
=
respectively so maximum will be A+B= +=8.99 and minimum be 1.78
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