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`        The length of a second hand in a watch is 1cm. Find the change in  velocity of its tip in 15s? `
4 years ago

Saurabh Kumar
2411 Points
```							Here, |V1| = |V2| = (pi/30)cm/s.Thus the change in the magnitude of the velocity of the second's hand in 15 seconds is -[{pi*sqrt(2)}/30]cm/s
```
4 years ago
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• Test paper with Video Solution
• Mind Map
• Study Planner
• NCERT Solutions
• Discussion Forum
• Previous Year Exam Questions