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The area of cross section of a wire is 10 -5 m 2 . When irs length is increased by 0.1% a tension of 1000N is produced. What will be the youngs modulus of the wire.

```
4 years ago

Vikas TU
14146 Points
```							We know the Young’s modulus formulae:Y = Fl/Adelta(l)   = 1000l/(10^-5 * (1/10000))   = 10^7/10^-5   = 10^12 N/m^2
```
4 years ago
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