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Question no. 22 solution please . How i get the answer

dilip kumar , 7 Years ago
Grade 12th pass
anser 3 Answers
Eshan
Dear student,

Since the vectors form a right angled triangle,Bsin\theta=R=\dfrac{B}{\sqrt{2}}

\implies sin\theta=\dfrac{1}{\sqrt{2}}
\implies \theta=45^{\circ}
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Last Activity: 7 Years ago
prateek
We have the vertical component of vector B = B sinθ
The vertica component will be equal to the resultant vector.
 B Sinθ = B/√2
we get   
Sinθ= 1/√2 
Angle b/w vectors is 
 
Last Activity: 7 Years ago
prateek
 
 
We have the vertical component of vector B = B sinθ
The vertica component will be equal to the resultant vector.
 B Sinθ = B/√2
we get   
Sinθ= 1/√2 
Angle b/w vectors is 45°
Last Activity: 7 Years ago
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