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Grade: 11

                        

Q. The moment of inertia of a uniform rod of length L and mass M about an axis through centre and perpendicular to length is given by ML^2/12. Now consider one such rod pivoted at its centre free to rotate in a vertical plane. The rod is at rest in the vertical position. A bullet of mass M moving horizontally at a speed v strikes and gets embedded in one end of the rod. The angular velocity w of the rod after collision will be1) v/L2) 2v/L3) 3v/L4) 6v/L

3 years ago

Answers : (1)

Saurabh Koranglekar
askIITians Faculty
8407 Points
							576-438_q.PNG
						
5 months ago
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